Question

answer this question​

Answer 1

Answer:

a=1

b^2=2

therefore

a+b^2=3

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Solution:-}}}}}}$.

$\large{\underline{\underline{\mathfrak{\sf{Given\:Here:-}}}}}$.

★Equation Of Polynomial .

✴$\:x^2-3x^2+x+1\:=0$.

➡Root of given equation :-

✴a-b , a , a+b .

$\large{\underline{\underline{\mathfrak{\sf{Explanations:-}}}}}$.

➡We know that

$\bold{\:Sum\:of\:Roots\:=\frac{\:-(Cofficient\:of\:x^2)}{\:(Cofficient\:of\:x^3)}}$.

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$\implies\:(a-b)\:+\:(a)\:+\:(a+b)\:=\frac{-(-3}{1}$

$\implies\:(3a)\:=\:-3$.

$\implies\:a\:=\frac{3}{3}$.

$\implies\:a\:=\:1$.

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Now,

✴$\bold{\:Product\:of\:Root\:=\frac{-(Constant\:part)}{(Coefficient\:of\:x^3)}}$.

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$\implies\:(a-b)(a)(a+b)\:=\frac{-(1)}{1}$

$\implies\:(1-b)(1)(1+b)\:=\:-1$.

$\implies\:(1-b^2)\:=\:-1$.

$\implies\:b^2\:=\:2$.

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$\large{\underline{\underline{\mathfrak{\sf{Find\:here:-}}}}}$.

✴$\bold{\:(a+b^2)}$.

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So,

$\implies\:a\:+\:b^2\:=\:1\:+\:2$.

$\red{\implies\:a\:+\:b^2\:=\:3}$.

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