Math, asked by ab295236, 10 months ago

answer this question

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Answered by sandy1816

1

Step-by-step explanation:

cosA-sinA=√2sinA

(cosA-sinA)²=2sin²A

1-2sinAcosA=2sin²A

1-2sinAcosA=2(1-cos²A)

1-2sinAcosA=2-2cos²A

-1-2sinAcosA=-2cos²A

sin²A+cos²A+2sinAcosA=2cos²A

(sinA+cosA)²=2cos²A

sinA+cosA=√2cosA

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