Question

answer this question​

Answer 1

Answer:

Step-by-step explanation:

since sinA=1/2

A=π/6

3cosA-4$cos^{3}$A=3$\frac{\sqrt{3} }{2}$ - 4$(\frac{\sqrt{3} }{2})^{3}$

=3$\frac{\sqrt{3} }{2}$ -4$\frac{(3)\sqrt{3} }{8}$

=3$\frac{\sqrt{3} }{2}$ - 3$\frac{\sqrt{3} }{2}$ = 0

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