Question

answer this question​

Answer 1

$\Larfe{\underline{\underline{\bf{Solution :}}}}$

★ Given :

A.P : 0, 1, 2, 3, 4........50

First term (a) = 0

Last term (An) = 50

Common Difference (d) = 1

__________________________

★ To Find :

We have to find the number of terms (n).

__________________________

★ Explanation :

We know that,

$\Large{\implies{\boxed{\boxed{\sf{A_n = a + (n - 1)d}}}}}$

______________[Put Values]

$\sf{→ 50 = 0 + (n - 1)1} \\ \\ \sf{→ 50 = (n - 1)} \\ \\ \sf{→ n = 50 + 1} \\ \\ \sf{→ n = 51} \\ \\ \Large{\implies{\boxed{\boxed{\sf{n = 51}}}}} \\ \\ \sf{ \therefore \: Number \: of \: terms \: are \: 51}$

Answer 2

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

The AP is 0 , 1 , 2 , 3 , ...... , 49

Here ,

First term (a) = 0

Common difference (d) = 1

Last term (an) = 49

We know that , the first n terms of an AP is given by

$\mathtt{\large\fbox{ a_{n} = a + (n - 1)d}}$

Thus ,

49 = 0 + (n - 1)1

49 = n - 1

n = 50

Hence , there are 50 whole numbers which are less then 50

_______________ Keep Smiling ☺