answer this question
Attachments:
Answers
Answered by
2
Answer:
⚜⭐When 8 and 12 are in parallel
When 8 and 12 are in parallel and 7.2 is in series with them
When 8 and 12 are in parallel and 7.2 is in series with them Net Resistance 107.2+12+88×12
When 8 and 12 are in parallel and 7.2 is in series with them Net Resistance 107.2+12+88×12=1072+2096=1072+1048=10120=12Ω
When 8 and 12 are in parallel and 7.2 is in series with them Net Resistance 107.2+12+88×12=1072+2096=1072+1048=10120=12ΩTotal current =netRV=126=0.5Ω
When 8 and 12 are in parallel and 7.2 is in series with them Net Resistance 107.2+12+88×12=1072+2096=1072+1048=10120=12ΩTotal current =netRV=126=0.5ΩVoltage across R1=iR1=0.5×7.2=3.6
I HOPE IT HELPS YOU:)
Explanation:
LIKE,VOTE,FOLLOW PLEASE :)
MARK MY ANSWER BRAINLIST PLEASE :)
⚜⭐⭐❤❤⤵️⤵️
Attachments:
Similar questions