Question

Answer This Question ​

Answer 1

Answer:

Step-by-step explanation:

No of baby suits that can be made = 37 1/2 ÷ 5/7

= 52

Amount left = 0.5 m

Answer 2

Answer :

Given :

$\textsf{Total material available for making the baby suits = }{\tt{ 37 \times \dfrac{1}{2}meters}}$

$\textsf{Length of the material required for making 1 baby suit =}{\tt{\dfrac{5}{7}meters}}$

Required to find :

1. How many baby suits can be made ?
2. How much material will be left ?

Explanation :

In the question it is given that ,

A tailor has 37*1/2 meters total material to make the baby suits .

He requires 5/7 meters to prepare 1 baby suit .

And he asked us to find the number of suits can be prepared and how much material will be left .

Solving this question is very simple .

But you need to apply a little bit of logic .

Here, is the explanation of the whole sum

First we have to find the number of suits which can be prepared .

This can be found by ;

Dividing the total length of the material the tailor has by length of the material required per suit .

This is represented as ;

$\boxed{\tt{No. \: of \: suits = \dfrac{Total \: material}{Material \: required \: for \: per \: suit}}}$

Using this we can find the number of suits which can be prepared .

Similarly, we have to find the material left .

This is found in 2 steps;

1st step :

we have to multipy the no. of suits which can be prepared with Material required to prepare per suit .

This enables us to find the material he used to prepare the suits .

Step - 2 :

Subtract the Total length of the material with Length of the material required for prepared suits .

Hence, your question is Solved .

Solution :

$\textsf{Total material available for making the baby suits = }{\tt{ 37 \times \dfrac{1}{2}meters}}$

$\textsf{Length of the material required for making 1 baby suit =}{\tt{\dfrac{5}{7}meters}}$

using the formula;

$\boxed{\tt{No. \: of \: suits = \dfrac{Total \: material}{Material \: required \: for \: per \: suit}}}$

So, substitute the respective values ;

$\longrightarrow{\tt{No. \: of \: suits = \dfrac{37 \times \dfrac{1}{2} }{\dfrac{5}{7}}}}$

This is written as ,

$\tt{ No.\: of \:shirts = 37 \times \dfrac{1}{2} \div \dfrac{5}{7}}$

Convert the mixed fraction into improper fraction ;

$\tt{No.\: of \;suits = \dfrac{75}{2} \div {5}{7}}$

$\tt{No.\;of \; suits = \dfrac{75}{2} \times {7}{5}}$

$\tt{No. \; of \; suits = \dfrac{15}{2} \times {7}{5}}$

$\tt{ No. \; of \; suits = \dfrac{105}{2}}$

$\tt{No. \; of \; suits = 52.5 }}$

$\green{\implies{\tt{ No. \; of \; suits = 52 \; suits }}}$

Similarly,

Let's find the material left in 2 steps ;

Step - 1 .

Total material he used = No. of suits x Material required for per suit

Total material he used = 52 x 5/7

Total material he used = 260/7

Total material he used = 37.14

Total material he used = 37 meters

Step - 2

Subtract the Total material he had with Total material he used

$\tt{Material \;left = \dfrac{75}{2} - {37}{1}}$

$\tt{Material\;left = \dfrac{ 75 - 74 }{2}}$

$\tt{ Material \; left = \dfrac{ 1}{2}}$

$\tt{\red{\implies{ Material \; left = 0.5 meters }}}$

Hence Solved .