Question

answer this question​

Answer 1

Let the odd numbers be 2n+1 and 2n+3

difference of squares of consecutive integer=

= (2n+3)²-(2n+1)²

= 4n²+9+12n-4n²-1-4n

= 8n+8

= 8(n+1)

it is divisible by 8

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Answer 2

answer is 3

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