Question

Answer this question​

Answer 1

$\sqrt{12} = \sqrt{2 \times 2 \times 3} = 2 \sqrt{3}$

$\sqrt[3]{16} = \sqrt[3]{2 \times 2 \times 2 \times 2} = 2 \sqrt[3]{2}$$\sqrt[6]{320} = \sqrt[6]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5} = 2 \sqrt[6]{5}$$2 \sqrt{3} > 2 \sqrt[3]{2} > 2 \sqrt[6]{5}$

$\sqrt{12} > \sqrt[3]{16} > \sqrt[6]320}$

PLEASE MARK BRAINLIEST

Answer 2

Step-by-step explanation:

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