Question

answer this question ​

Answer 1

Answer:

The range is maximum for the angle $45^o$.

Answer 2

Here's ur answer

The equation of range is given by,

Range = u²sin2Ѳ/g

For range to be maximum, sin2Ѳ should be max

The maximum value that sin2Ѳ can have is 1

Hence,

sin2Ѳ = 1

2Ѳ = 90°

Ѳ = 45°

Therefore, for a shot-put to have maximum range it should be thrown at an angle 45°

Hope it helps