Question

Answer this question!​

Answer 1

Step-by-step explanation:

▪️Solution:

▪️Since AB is a straight line,

▪️∴ ∠AOC + ∠COE + ∠EOB = 180°

▪️or (∠AOC + ∠BOE) + ∠COE = 180° or 70° +

▪️∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

▪️or ∠COE = 180° – 70° = 110°

▪️∴ Reflex ∠COE = 360° – 110° = 250°

▪️Also, AB and CD intersect at O.

▪️∴∠COA = ∠BOD [Vertically opposite angles]

▪️But ∠BOD = 40° [Given]

▪️∴ ∠COA = 40°

▪️Also, ∠AOC + ∠BOE = 70°

▪️∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

▪️Thus, ∠BOE = 30° and reflex ∠COE = 250°.

Hopes it help you✌️✌️

Answer 2

Answer:

ang aoc plus ang now is 70

ang bod ia 40, ang bod is same as ang aoc. alternate angles.

aoc is then 40 boe is 30.

180-70=110

coe is 110

360-110=250 degre

250 is reflex coe