answer this question ???
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Answer:
Step-by-step explanation:
Formula for sum of n terms of an AP is
Sn = n/2(2a+(n-1)d)
=> According to question
5n^2+3n=r.h.s
n(5n+3)=n/2(2a+(n-1)d)
Cancel n both sides
(5n+3)2=2a+(n-1)d
Answered by
0
Answer:
thanks for this question
Step-by-step explanation:
first of all, formula of n term AP is Sn= n/2(2a+(n-1)d
now let's start,
5n^2+3n= r.h.s
n(5n+3)=n/2(2a+n-1)d
(5n+3)2=2a+(n-1)d
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