Question

answer this question​

Answer 1

Answer:

Log a/y-z=log b/z-x= log c/x-y=k

x Log a=k(y-z)

y log b=k(z-x)

Z log c=k(x-y)

Add all the above equations

log a^x+log b^y+log c^z=k[y-z+z-x+x-y]

Log[a^x b^y c^z] =0=log 1

a^x b^y c^z=1