Question

Answer this question ​

Answer 1

Step-by-step explanation:

In line AZ,

AOC + COZ

100° + COZ =180° (linear pair)

COZ =80°

In Line AZ,

ZAB + AZD =180° (AB || CD)

120° + OZC =180°

OZC = 60°

In ∆OCZ,

COZ+OZC+OCZ = 180 (Angel Sum Property)

80 + 60 + OCZ= 180

OCZ =40°

Thus, x= 40° (vertically opposite angel)

Answer 2

Answer:

x = 40°

Step-by-step explanation:

construct a line PQ parallel to AB and CD intersecting point O...

angle AOQ + 120° = 180° ...(co-interior angles)

angle AOQ = 180°-120° = 60°

angle O = 60° + angle QOC = 100°

angle QOC = 100°-60° = 40°

angle QOC = angle C = x = 40° ..... ( corresponding angles)

Hence, x = 40°