Math, asked by meghatripathi077, 8 months ago

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Answered by ranjana64
1

2x2 + y2 + 8z2 - 2√(2xy) + 4√(2yz) - 8xz

= (-√2x)2 + y2 + {2√(2z)}2 - 2{(-√2x)*y} + 2y*{2√(2z)} + 2*(-√2x)*{2√(2z)}

= {-√2x + y + 2√(2z)}2

= {-√2x + y + 2√(2z)}*{-√2x + y + 2√(2z)}

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Answered by TheQuantumMan
1

Answer:

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ans. attached above.........

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