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Step-by-step explanation:
√2+√3 = p/q
p/q-√3=√2
squaring on both sides we get,
= [p/q - √3]² = (√2)²
= p²/q² - 2p/q √3+3=2
= p²/q²+3-2 = 2√3p/q
= p²/q²+1= 2√3p/q
= [p²+q²/q²] *q/2p = √3
= p²+q²/2pq = √3
= √3 is a rational number.
{ therefore pq are integers
p²+q²/2pq are rational}
this contradicates the fact that √3 is irretational
so assumption was incorrect . hear √2+√3 is irrational.
hope it helps you.
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