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we know,
magnification(mirror) = -v/u. = h2/h11
therefore
-v/-15 = 3/-2
v/15. = 3/-2
v = 15×3/-3
v = 45/-2
v = -22.5cm
PLEASE NOTE THAT (-) SIGN INDICATES
magnification(mirror) = -v/u. = h2/h11
therefore
-v/-15 = 3/-2
v/15. = 3/-2
v = 15×3/-3
v = 45/-2
v = -22.5cm
PLEASE NOTE THAT (-) SIGN INDICATES
Answers
Answered by
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HEY ...YOUR ANSWER :
As we know that , -v/u = h°/h
Therefore , -v = (h°/h ) × u
Here , h°= - 3cm {-ve ,due to the formation of a real image} , h = 2 cm , u = -15cm
Now -v = (-3/2)×-15cm
-v = 45/2. cm
-v = 22.5 cm
v = - 22.5 cm
Hence , the image is at -22.5 cm.
HOPE MY ANSWER WILL HELP YOU !!!
As we know that , -v/u = h°/h
Therefore , -v = (h°/h ) × u
Here , h°= - 3cm {-ve ,due to the formation of a real image} , h = 2 cm , u = -15cm
Now -v = (-3/2)×-15cm
-v = 45/2. cm
-v = 22.5 cm
v = - 22.5 cm
Hence , the image is at -22.5 cm.
HOPE MY ANSWER WILL HELP YOU !!!
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Answered by
0
h1= +2. (since the object is always erect
therefore it will take +ve sign)
h2= -3. (since the image is real therefore
it will be inverted and hence will
take a -ve sign)
now,
u. = -15
magnification(mirror) = -v/u. = h2/h11
therefore
-v/-15 = 3/-2
v/15. = 3/-2
v = 15×3/-3
v = 45/-2
v = -22.5cm
Similar questions
therefore it will take +ve sign)
h2= -3. (since the image is real therefore
it will be inverted and hence will
take a -ve sign)
now,
u. = -15
so, v = ?