Question

answer this question ​

Answer 1

$\sf\blue{{(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca}$

$\sf\blue{= >{( a + b + c) }^{2} - 2ab - 2bc - 2ca }\\ \blue{= \sf{( a + b + c) }^{2} - 2(ab + bc)}$

$\sf \blue{ = > 100 - 2(50) = 100 - 100 = 0}$

We know that a+b+c = 10;

ab+bc+cd = 50;

Then Find a²+b²+c²

Conclusion:-

a²+b²+c²=0