Math, asked by Deependrasingh1, 1 year ago

answer this question.....

Attachments:

Answers

Answered by hardiksharmah10
1
Let the days he was absent marked as y.

Money cut off for absence = (10 x y)

And the days he was present marked as z.

Money gained by working = (120 x z)

Now, (120 x z) - (10 x y) = Total Money he received = 1880

120z - 10y = 1880

12z - y = 188

z + y =20 = Total number of days he worked

y = 20 - z

-y = z-20

Putting this value in the equation before,

12z + (z - 20) = 188

13z = 208

z = 16.
y = 4

So he remained absent for 4 days.

Hope it helps you.

Please mark as the Brainliest if it did.
 

 

hardiksharmah10: Please mark Brainliest if it was helpful
Answered by amit4711
2
Labour is engaged for = 20days
Rate for 1day = Rs 120
Money earned in 20 days = 20×120 => Rs 2400
Fine for 1day absent = Rs. 10
Total money he got =Rs 1880
No. Of day he was absent = 2400 - 1880 = 520
=> 520/10 = 52days


Deependrasingh1: how it was 52 days....if he was working for 20days only...?
amit4711: I got it
Similar questions