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Let the days he was absent marked as y.
Money cut off for absence = (10 x y)
And the days he was present marked as z.
Money gained by working = (120 x z)
Now, (120 x z) - (10 x y) = Total Money he received = 1880
120z - 10y = 1880
12z - y = 188
z + y =20 = Total number of days he worked
y = 20 - z
-y = z-20
Putting this value in the equation before,
12z + (z - 20) = 188
13z = 208
z = 16.
y = 4
So he remained absent for 4 days.
Hope it helps you.
Please mark as the Brainliest if it did.
Money cut off for absence = (10 x y)
And the days he was present marked as z.
Money gained by working = (120 x z)
Now, (120 x z) - (10 x y) = Total Money he received = 1880
120z - 10y = 1880
12z - y = 188
z + y =20 = Total number of days he worked
y = 20 - z
-y = z-20
Putting this value in the equation before,
12z + (z - 20) = 188
13z = 208
z = 16.
y = 4
So he remained absent for 4 days.
Hope it helps you.
Please mark as the Brainliest if it did.
hardiksharmah10:
Please mark Brainliest if it was helpful
Answered by
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Labour is engaged for = 20days
Rate for 1day = Rs 120
Money earned in 20 days = 20×120 => Rs 2400
Fine for 1day absent = Rs. 10
Total money he got =Rs 1880
No. Of day he was absent = 2400 - 1880 = 520
=> 520/10 = 52days
Rate for 1day = Rs 120
Money earned in 20 days = 20×120 => Rs 2400
Fine for 1day absent = Rs. 10
Total money he got =Rs 1880
No. Of day he was absent = 2400 - 1880 = 520
=> 520/10 = 52days
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