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s1 = 1 + 2 = 3 = a1
s2 = 4 + 2×2 = 8
since
s2 = a1 + a2
hence
a2 = s2 - a1 = 8 - 3 =5
d = a2 - a1 = 5 - 3 = 2
tn = a1 +(n - 1)d
tn = 3 + (n-1)2
tn = 3 + 2n - 2
tn = 2n +1
is the
answer
of the
question
s2 = 4 + 2×2 = 8
since
s2 = a1 + a2
hence
a2 = s2 - a1 = 8 - 3 =5
d = a2 - a1 = 5 - 3 = 2
tn = a1 +(n - 1)d
tn = 3 + (n-1)2
tn = 3 + 2n - 2
tn = 2n +1
is the
answer
of the
question
yashraj161:
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