Question

answer this question ⁉️​

Answer 1

Answer:

(b) 116 is correct option

Step-by-step explanation:

a^2 + b^2 = (a + b)^2 - 2ab

= (12)^2 - 2×14

= 144 - 28 = 116

Answer 2

Given :

• (a+b)= 12
• ab = 14

To Find :

The value of (a²+b²)

Solution :

We have to Find the value of a²+b²

We know that

$\sf{(a+b)^2=a^2+b^2+2ab}$

Now , Put the given values

$\sf\implies\:(12)^2=a^2+b^2+2(14)$

$\sf\implies\:144=a^2+b^2+28$

$\sf\implies\:144-28=a^2+b^2$

$\sf\implies\:a^2+b^2=116$

Therefore, the value of a²+b² is 116

Correct option b ) 116

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Algeberaic Indentities:

1)$\sf{(a+b)^2=a^2+b^2+2ab}$

2)$\sf{(a-b)^2=a^2+b^2-2ab}$

3)$\sf{(a^2-b^2)=(a+b)(a-b)}$

$4)\sf{(a+b+c)^2={a}^{2}+{b}^{2}+{c}^{2}+2ab+2bc+2ca}$

5)$\sf{(a+b)^3=a^3+b^3+3ab(a+b)}$