Question

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Answer 1

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ATQ,

Area of hollow cylinder =Area of rectangle

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To find perimeter of rectangler sheet we must have lenght(l) and breadth.

But we don't have length.(Breadth=33cm)

So,

Area of rectangle:-

$l \times b$

$or \\ 4224 = l \times 33$

$or \\ 4224 \div 33 = l$

$so \\ l = 128 \: cm$

Given:-

$length = 128 \: m$

$bredth = 33 \: cm$

$perimeter =?$

So,now we have to find Perimeter of Rectangle.....

$p = 2(l + b)$

$p = 2(128 + 33)$

$p = 2(161)$

$p = 322 \: m$

So, Perimeter of a rectangle sheet is 322 cm...

Hope it helps U✌️✌️✌️...

Answer 2

Answer:

Here is your answer:-

Length of the rectangle will be equal to the circumference (2πr) of a circle end and the breadth will be equal to the height h of the cylinder.

Given:-

Lateral surface area of a hollow cylinder = 4224cm^2

Height of a hollow cylinder (h) = 33cm

Lateral surface area or curved surface area of hollow cylinder = 2πrh

4224 = 2 × 22/7 × r × 33

r = (4224 × 7) /2 × 22 × 33

r = (64 × 7) /22

Length of rectangular sheet = 2πr

= 2 × (22/7) × 64 × 7/22

= 64 × 2

= 128 cm

Perimeter of rectangular sheet = 2 × (l+b)

= 2 × (128+33)

= 2 × 161

= 322 cm

Hence, perimeter of rectangular sheet is 322 cm

Hope it helps uh......

Have a great day......