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let once place digit be x and
the another digit at tense place is 9-x
the original no is 10(9-x)
when we inter changed then the no is 10x + 9-x.
According to the problem.
10x+9x-x=10(9-x)+x+27
*10x+9-x=90-10x+x+27
*9x+9=-9+117.
*9x+9x=117-9= 108.
*18x=108.
x=108/18
=6.
•: the no is 10(9-x)+x
=10(9-6)+6
=30+6
36.
I hope it will help you
Mind it .....
the another digit at tense place is 9-x
the original no is 10(9-x)
when we inter changed then the no is 10x + 9-x.
According to the problem.
10x+9x-x=10(9-x)+x+27
*10x+9-x=90-10x+x+27
*9x+9=-9+117.
*9x+9x=117-9= 108.
*18x=108.
x=108/18
=6.
•: the no is 10(9-x)+x
=10(9-6)+6
=30+6
36.
I hope it will help you
Mind it .....
susmitataria2:
why the original number multipled by 10
because once place digit is x . and then tense place is 10....
that means we have to multiply by 10...
with another no....
Ohoo OK thanks
welcome ...like it ....
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