Question

answer this question......,

Answer 1

Here I am writing theta as A as it is difficult for me to write theta always.

Let the given points be A(cosA, sinA) and B(-sinA,cosA).

x1 = cosA, x2 = -sinA, y1 = sinA, y2 = cosA.

Therefore the distance between the points:

$AB = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

             $= \sqrt{(-sinA - cosA)^2 + (cosA - sinA)^2}$

            $= \sqrt{sin^2A + 2sinAcosA + cos^2A + cos^2A + sin^2A - 2sinAcosA}$

            $= \sqrt{2sin^2A + 2cos^2A}$

            $= \sqrt{2(sin^2A + cos^2A)}$

            $= \sqrt{2(1)}$

            $= \sqrt{2}$


Therefore the answer is the option (B) - root 2.



Hope this helps!

Answer 2

Hi,

Please see the attached file!



Thanks