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found in my tb the answer hope that it helps you
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I have given you 2 answers 1 answer is in the text and another answer is in the attachment please see it, or the better understanding.
question:
a bullet of mass m moving with velocity v strikes a suspended wooden block of mass m and sticks to it. if the block rises to a height h, the initial velocity of the bullet will be:-
Solution:
Initial KE of block when bullet strikes to it
=1/2(m+M)v². Due to this KE of block will rise to a height h. Its potential energy =(m+M)gh. By the law of conservation of energy.1/2(m+M)v²=(m+M)gh.
v=√2gh.
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