Question

Answer this question.... ​

Answer 1

Step-by-step explanation:

Take LCM

(5x-25-2x+6)/10 =1/2

(3x-19)/10 =1/2

(3x-19) = 10*1/2

3x-9 = 5

3x=5+9

3x=14

x= 14/3

Answer 2

Let's solve your equation step-by-step.

$\dfrac{x-5}{2} - \dfrac{x-3}{5}=\dfrac{1}{2}$

Step 1: Simplify the equation.

⇒ $\dfrac{x-5}{2} - \dfrac{x-3}{5}=\dfrac{1}{2}$

⇒ $\dfrac{(x-5)\times 5 }{2\times 5} - \dfrac{(x-3)\times 2 }{5\times 2 }=\dfrac{1}{2}$

⇒ $\dfrac{5x-25 }{10} - \dfrac{2x-6 }{10 }=\dfrac{1}{2}$

⇒ $\dfrac{5x-25-2x+6 }{10} =\dfrac{1}{2}$

(Combine Like Terms)

⇒ $\dfrac{5x-2x-25+6 }{10} =\dfrac{1}{2}$

⇒ $\dfrac{3x-19}{10} =\dfrac{1}{2}$

Step 2: Cross multiply.

⇒ $\dfrac{3x-19}{10} =\dfrac{1}{2}$

⇒ $2(3x-19)=1(10)$

⇒ $6x - 38=10$

Step 3: Add 38 to both sides of the equation.

⇒ $6x - 38+38=10+38$

⇒ $6x = 48$

Step 4: Divide 6 from both sides of the equation.

⇒ $\dfrac{6x}{6} =\dfrac{48}{6}$

⇒ $x = 8$

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Let's verify if 'x' = 8

⇒ $\dfrac{x-5}{2} - \dfrac{x-3}{5}=\dfrac{1}{2}$

⇒ $\dfrac{8-5}{2} - \dfrac{8-3}{5}=\dfrac{1}{2}$

⇒ $\dfrac{3}{2} - \dfrac{5}{5}=\dfrac{1}{2}$

⇒ $\dfrac{3}{2} - 1 = \dfrac{1}{2}$

⇒ $\dfrac{3}{2} - \dfrac{2}{2} = \dfrac{1}{2}$

⇒ $\dfrac{1}{2} = \dfrac{1}{2}$

∴ LHS = RHS

∴ x = 8 in the given equation.

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