Question

answer this question​

Answer 1

Answer:

Step-by-step explanation:

Given:

$\angle ACB=90^\circ$

$\angle ACD=\angle ACB=90^\circ$

$AB=10 cm$

$BC=6cm$

$AD=17cm$

To find:

1. AC

$\because (height)^2 = (hypotenuse)^2-(base)^2$

$\implies AC^2 =10^2-6^2$

$\implies AC^2=100-36$

$\implies AC^2= 64cm$

$\implies AC=\sqrt{64cm}$

$\implies AC=8cm$

2. CD

$\because (base)^2 = (hypotenuse)^2-(height)^2$

$\implies CD^2 =17^2-8^2$

$\implies CD^2=289-64$

$\implies CD^2= 225cm$

$\implies CD=15cm$

Answer 2

ANSWER.

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