Question

Answer this question​

Answer 1

Answer:

$(2x + 3y)(2x + 3y)$

$= 2x(2x + 3y) + 3y(2x + 3y)$

$= 4 {x}^{2} + 6xy + 6xy + 9 {y}^{2}$

$= 4 {x}^{2} + 12xy + 9 {y}^{2}$

$(4p - 3q)(4p - 3q)$

$= 4p(4p - 3q) - 3q(4p - 3q)$

$= 16 {p}^{2} - 12pq - 12pq + 9 {q}^{2}$

$= 16 {p}^{2} - 24pq + 9 {q}^{2}$

$(6x - 7y)(6x + 7y)$

$= 6x(6x + 7y) - 7y(6x + 7y)$

$= 36 {x}^{2} + 42xy - 42xy + 49 {y}^{2}$

$= 36 {x}^{2} + 49 {y}^{2}$

$(4x + 5)(4x - 1)$

$= 4x(4x - 1) + 5(4x - 1)$

$= 16 {x}^{2} - 4x + 20x - 5$

$= 16 {x}^{2} + 16x - 5$

HOPE IT HELPS.

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Answer 2

Answer:

(i) (2x + 3y )(2x + 3y)

This can be written as (2x + 3y)²

Using Identity (a + b)² = a² + 2ab + b²

( 2x + 3y )² = (2x)² + 2×2x×3y + (3y)²

4x² + 12xy + 9y² ans.

(ii) ( 4p - 3q )( 4p - 3q )

This can be written as (4p - 3q)²

Using Identity ( a - b )² = (a)² - 2ab + (b)²

( 4p - 3q )² = (4p)² - 2×4p×3q + (-3q)²

16p² - 24pq + 9q² ans.

(iii) ( 6x - 7y )( 6x + 7y )

Using Identity ( a + b )( a - b) = (a)² - (b)²

( 6x - 7y )( 6x + 7y ) = (6x)² - (7y)²

36x² - 49y² ans.

(iv) (4x + 5 )( 4x - 1 )

Here no Identity can be used so, we have multiple it

( 4x + 5 )(4x - 1 ) = 4x( 4x + 5 ) + 5( 4x - 1 )

16x² + 20x + 20x - 5

16x² + 40x - 5 ans.

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