Math, asked by aaseshan123, 3 months ago

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Answered by senboni123456
0

Step-by-step explanation:

We have,

 \int \limits^{3}_{2} \int \limits^{2}_{1} \frac{dxdy}{xy}  \\

  = \int \limits^{3}_{2} (\int \limits^{2}_{1} \frac{dx}{x}  ) \frac{dy}{y} \\

  = \int \limits^{3}_{2} ([ ln(x) ] ^{2}_{1}    ) \frac{dy}{y} \\

  = \int \limits^{3}_{2}  ln(2)  \frac{dy}{y} \\

  =  ln(2) \int \limits^{3}_{2} \frac{dy}{y} \\

  =  ln(2)  [ ln(y) ] ^{3}_{2} \\

 =  ln(2) ( ln(3)  -   ln(2) )

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