Question

answer this question​

Answer 1

Answer:

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Answer 2

$\mathtt\red{SOLUTION:-}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mathfrak{ {t}^{2} - 15 = 0 }$

$\mathfrak{ {t}^{2} = 0 + 15}$

$\mathfrak{ {t}^{2} = 15 }$

$\mathfrak{t = \sqrt{15} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mathtt\red{SECOND \: QUES}$

$\mathtt{SUM \: OF \: THE \: ZEROS}$

$\mathtt \red{ \alpha + \beta = \frac{ - b}{a} }$

$\mathtt \red{ \frac{1}{4} \: \: \: = \frac{ - b}{a} }$

$\mathtt\red{ \frac{ - 1}{4} = \frac{b}{a} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mathtt{PRODUCT \: OF \: THE \: ZEROS}$

$\mathtt \red{ \alpha \beta = \frac{c}{a} }$

$\mathtt \red{ - 1 = \frac{c}{a} }$

$\mathtt \red{ \frac{ - 1 \times 4}{ 1\times 4} = \frac{c}{a} }$

$\mathtt \red{ \frac{ - 4}{4} = \frac{c}{a} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mathtt{GENERAL \: FORM \: OF \: QUADRATIC \: EQUATION}$

$\mathtt \red{ = {ax}^{2} + bx + c }$

$\mathtt \red{ = {4x}^{2} - x - 4 }$