Question

answer this question​

Answer 1

Answer:

he is difficult but his question is very interesting

(x2−5x+7)2−(x−2)(x−3)=1(x2−5x+7)2−(x−2)(x−3)=1

(x2−5x+7+x−5x+6)(x2−5x+7−(x2−5x+6)=1[A2−B2=(A+B)(A−B)](x2−5x+7+x−5x+6)(x2−5x+7−(x2−5x+6)=1[A2−B2=(A+B)(A−B)]

(2x2−10x+13)(x2−5x+7−x2+5x−6)=1(2x2−10x+13)(x2−5x+7−x2+5x−6)=1

Answer 2

$\huge\bold{\mathtt{\red{A{\pink{N{\green{S{\blue{W{\purple{E{\orange{R}}}}}}}}}}}}}$

(x2−5x+7)2−(x−2)(x−3)=1(x2−5x+7)2−(x−2)(x−3)=1

(x2−5x+7+x−5x+6)(x2−5x+7−(x2−5x+6)=1[A2−B2=(A+B)(A−B)](x2−5x+7+x−5x+6)(x2−5x+7−(x2−5x+6)=1[A2−B2=(A+B)(A−B)]

(2x2−10x+13)(x2−5x+7−x2+5x−6)=1(2x2−10x+13)(x2−5x+7−x2+5x−6)=1