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Answered by Ara07
1

Let us assume, to the contrary, that 2√5 − 3 is a rational number

∴ 2√5 − 3 = p/q,

where p and q are integers and q ≠ 0

⇒ √5 = p+3q/2q... (1)

Since p and q are integers

∴ p +3a/2q is a rational number

∴ √5 is a rational number which is a contradiction as √5 is an irrational number

Hence our assumption is wrong and 2√5 − 3 is an irrational number.

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