answer this question
Attachments:
Answers
Answered by
1
Hi there!
Here's your answer :-
Given :--
x = 1 / x - 5
=> x - 1 / x = -5
On squarin' both sides --
(x - 1 / x)² = (-5)²
=> x² + 1 / x² = 27
=> (x + 1 / x)² - 2 = 27
=> (x + 1 / x)² = 29
=> (x + 1 / x) = ±√29
Now,
x² - 1 / x² = (x + 1 / x) (x - 1 / x)
→ CASE 1 :--
When, x + 1 / x = √29
=> (√29)(-5)
=> -5√29
→ CASE 2 :--
When, x + 1 / x = - √29
=> (-√29)(-5)
=> 5√29
Hence, The required answer iz :-
5√29 nd -5√29
Hope it helps!
Here's your answer :-
Given :--
x = 1 / x - 5
=> x - 1 / x = -5
On squarin' both sides --
(x - 1 / x)² = (-5)²
=> x² + 1 / x² = 27
=> (x + 1 / x)² - 2 = 27
=> (x + 1 / x)² = 29
=> (x + 1 / x) = ±√29
Now,
x² - 1 / x² = (x + 1 / x) (x - 1 / x)
→ CASE 1 :--
When, x + 1 / x = √29
=> (√29)(-5)
=> -5√29
→ CASE 2 :--
When, x + 1 / x = - √29
=> (-√29)(-5)
=> 5√29
Hence, The required answer iz :-
5√29 nd -5√29
Hope it helps!
Similar questions