Question

answer this question ​

Answer 1

Answer:

a): (p^2k)(q^-2k)(q^2k)(r^-2k)(r^2k)(p^-2k)

=[p^2k-2k] [q^2k-2k][r^2k-2k]

=p^0×q^0×r^0

=1×1×1= 1 Ans