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it is given that xsqu-3x-1=0
then xsqu-3x=1
taking x common
x(x-3)=1
x-3=1/x
x-1/x=3
squaring both sides
xsqu+1/xsqu-2=9
xsqu+1/xsqu=11
then xsqu-3x=1
taking x common
x(x-3)=1
x-3=1/x
x-1/x=3
squaring both sides
xsqu+1/xsqu-2=9
xsqu+1/xsqu=11
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