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- acceleration will be constant 'g' so slope of the graph will be constant.
- acceleration will be constant 'g' so slope of the graph will be constant.A & D are wrong.
- acceleration will be constant 'g' so slope of the graph will be constant.A & D are wrong.There will be discontinuity as at time of collision with the surface of glass and impulse will be very short timed. Initial the velocity will increase from zero till first collision.
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