Question

answer this question ​

Answer 1

Answer:

We use the common formula

NV= N₁V₁ + N₂V₂ + N₃V₃ ( where N= normality, V= volume )

Please note that this is only applicable in case of like solutions like acid- acid or base-base.

In order to calculate the final concentration of acid- base solutions, we will use the subtraction sign.

Given, final volume (V)= 100 ml, N₁ = M₁( n- factor )= M₁( 2)= 0.2 N

Similarly, N₂= 0.4 N, N₃ = 0.6 N, V₁= 20 ml, V₂= 30 ml, V₃= 30 ml

N= ?

Therefore, N× 100 = (20×0.2) + (30×0.4) + (30×0.6)

            ⇒  100 N= 4 + 12 + 18

            ⇒  100 N= 34

            ⇒  N= 0.34

Normality = 0.34 N,

therefore molarity= Normlaity/ n-factor= N/2= 0.17 M