Question

answer this question​

Answer 1

I hope you it is useful to you.

Answer 2

Answer:

Explanation:

1) Time period of simple pendulum  T = 2π $\sqrt{\frac{l}{g} }$

Since g at a place is constant,

∴ T ∝ $\sqrt{l}$

Since l₁ = l₂

$\frac{T_{1} }{T_{2} }$  = $\sqrt{\frac{l_{1} }{l_{2} } }$ = √ 1/1 = 1

∴ T₁ : T₂ = 1 : 1

Time period is independent of mass. It depends only on length and acceleration due to gravity.

2) T₁ : T₂ = 2 : 1

∴ $\frac{l_{1} }{l_{2} }$ = $[\frac{T_{1} }{T_{2} }] ^{2}$ = (2/1)² = 4

∴ l₁ : l₂ = 4 : 1