Question

answer this question ​

Answer 1

12. a).

$m + 2m + 3m = {180}^{0} \\ 6m = {180}^{0} \\ m = \frac{{180}^{0}}{6} \\m = {30}^{0}$

b). Three angles are:

$m = {30}^{0}$

$2m = 2 \times {30}^{0} = {60}^{0}$

$3m = 3\times {30}^{0} = {90}^{0}$

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