Question

answer this question​

Answer 1

Answer:

Given :  p(x) =  x² + x - 12

To Find : zeroes of the quadratic polynomial

verify the relationship between the zeroes and the coefficients

Solution:

 p(x) =  x² + x - 12

x² + x - 12  = 0

=> x² + 4x - 3x - 12 = 0

=> x (x + 4) - 3(x + 4) = 0

=> (x - 3)(x + 4) = 0

Zeroes are  3 , - 4

Sum of zeroes = 3 - 4 = - 1

Product of zeroes = 3(-4) = - 12

ax² + bx + c = 0

product of zeroes = c/a

sum of zeroes = - b/a

comparing  x² + x - 12  = 0  with ax² + bx + c = 0

a = 1  , b = 1  , c = - 12

product of zeroes = -12/1  = - 12

sum of zeroes = - 1/1  = - 1  

relationship between the zeroes and the coefficients verified

Answer 2

Answer:

7 and 8 is the answer

I think it helps you