Question

answer this question​

Answer 1

Step-by-step explanation:

Produce CD to cut AB at E.

Now, in ∆BDE, we have,

Exterior ∠CDB=∠CEB+∠DBE

⇒x=∠CEB+45 …..(i)

In ∆AEC, we have,

Exterior ∠CEB=∠CAB+∠ACE

=55+30=85

Putting ∠CEB=85 in (i), we get,

x=85+45=130

∴x=130