Physics, asked by roshni33, 1 year ago

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Answered by RiyuSharma
1
Hey
Here your answer
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Total Capacitance is
120/31
and q =cv
=120×300/31=36000/31
so the charge on 20, 12,8 microfarad's charge is 36000/31 micro colaumb.
one the 8 microfarad voltage is v=q/c
= 36000/31×8
= 4500/31
= 145.16
so voltage on 4 microfarad is 145 volte.
and charge is q = cv
= 4 ×145
=580 micro colaumb
so the right answer is D.

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Hope it helps you


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