Question

answer this question​

Answer 1

To Prove:- AO=BO

Solution:-

For, proving AO=BO, we've to prove those triangles are congruent,that is

∆AOD≈∆BOC

we know

AD=BC (given) (S)

angle OBC=angle OAD=90° (perpendicular) (A)

angle O = angle O (common angle) (A)

therefore by A.A.S congruence rule

∆AOD≈∆BOC

if,so

then by "Corresponding parts of congruent triangles",

AO=BO

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