Question

answer this question ​

Answer 1

Answer:

C) −3abc

Step-by-step explanation:

Given = a+b+c = 0

So

a+b = −c

b+c = −a

c+a = −b

a^2(b+c)+b^2(c+a)+c^2(a+b)

Putting values in eq.

a^2(−a)+b^2(−b)+c^2(−c)

−a^3−b^3−c^3 = −(a3+b3+c3)

We knowthat

(a3+b3+c3)=(a+b+c)(a2+b2+c2+3abc)

−(a3+b3+c3) = (0)(0+3abc)

−(a3+b3+c3) = 3abc

so

a^2(b+c)+b^2(c+a)+c^2(a+b) = −3abc

HOPE IT HELPS

Answer 2

Given a + b + c = 0

⇒ a3 + b3 + c3 = 3abc  → (1)

Consider, (a2/bc) + (b2/ca) + (c2/ab)

= (a3 + b3 + c3)/abc

= 3abc/abc = 3   [From (1)]..