Question

answer this question...​

Answer 1

Answer:

a) Yes

b) Yes

c) YES

Step-by-step explanation:

a) In triangle ABD and tri. ACD

AB=AC (equal sides of isocscles triangle)

AD=AD (common)

<BAD=<CAD (AD is the bisector of <A)

HENCE, PROVED

b) <ADB=<ADC (CPCT of triangles proved congruent in "a")

<ADB+<ADC=180° (Sum of angles on a straight line)

2<ADB =180°

<ADB = 180°/2

<ADB=90°

c) BD=DC (CPCT)

Therefore, D is the mid-point of BC

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