Math, asked by manisha7088, 4 days ago

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Answered by rajumanjula57
1

Answer:

\begin{gathered} {3x}^{2} + 5x + 2 = 0 \\ {3x}^{2} + (3 + 2)x + 2 = 0 \\ 3 {x}^{2} + 3x + 2x + 2 = 0 \\ 3x(x + 1) + 2(x + 1) = 0 \\ (3x + 2)(x + 1) = 0 \\ \\ now \\ \\ 3x + 2 = 0 \\ 3x = - 2 \\ x = \frac{ - 2}{3} \\ \\ x + 1 = 0 \\ x = - 1\end{gathered}

3x

2

+5x+2=0

3x

2

+(3+2)x+2=0

3x

2

+3x+2x+2=0

3x(x+1)+2(x+1)=0

(3x+2)(x+1)=0

now

3x+2=0

3x=−2

x=

3

−2

x+1=0

x=−1

Step-by-step explanation:

hope these will help you

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Answered by pafsar263
1

Step-by-step explanation:

answer is above and explaned

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