Question

answer this question ​

Answer 1

Answer:

(A ∪ B) - (A∩B) = {1, 2, 4, 6, 8, 10}

(A - B)∪(B-A) = {1, 2, 4, 6, 8, 10}

We observe that both the sets are equal.

Step-by-step explanation:

A = { 2, 4, 6, 8, 10}

A contains all natural numbers(all positive numbers starting from 1) less than 12 that are even.

B = { 1 }

B contains all odd natural numbers that are divisors of 6. So divisors of 6 are 1,2,3 and 6. So, as 1 is the only number that satisfies the condition we use 1 only in the set.

A ∪ B = {1, 2, 4, 6, 8, 10}

A ∪ B contains all elements of set A and B.

A∩B = {}

A∩B contains elements that are both in set A and set B. As there are no common elements in set A and B, A∩B is empty.

(A ∪ B) - (A∩B) = {1, 2, 4, 6, 8, 10}

(A ∪ B) - (A∩B) contains elements of A ∪ B that are not in A∩B. As A∩B is empty, the whole set A ∪ B will be the answer.

A-B = { 2, 4, 6, 8, 10}

A-B contains all elements of A that are not in B. As there are no common elements the whole set A is the answer.

B-A = {1}

B-A contains all elements of B that are not in A. As there are no common elements the whole set B is the answer.

(A - B)∪(B-A) = {1, 2, 4, 6, 8, 10}

(A - B)∪(B-A) is a set that contains all elements of A-B and B-A.