Math, asked by dinesh4884, 1 year ago

answer this question. ..............

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Answered by deekshantsinghal7996
0

x {}^{3}  - x {}^{2}  - x + 1
x+1=0
x= -1

p(x) =  - 1 \:  \:  \: =  ( - 1) {}^{3}  - ( - 1) {}^{2}  - ( - 1) + 1 \\  - 1 - 1 + 1 + 1 = 0 \\
yes it is a factor of p(x)
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