Question

answer this question

Answer 1

yoυr anѕwer !!

$= > \frac{7 + \sqrt{5} }{7 - \sqrt{5} } - \frac{7 - \sqrt{5} }{7 + \sqrt{5} } = a + 7b \sqrt{5} \\ \\ = > \frac{7 + \sqrt{5} }{7 - \sqrt{5} } \times \frac{7 + \sqrt{5} }{7 + \sqrt{5} } - \frac{7 - \sqrt{5} }{7 + \sqrt{5} } \times \frac{7 - \sqrt{5} }{7 - \sqrt{5} } = a + 7b \sqrt{5} \\ \\ = > \frac{ {(7 + \sqrt{5}) }^{2} }{ {(7)}^{2} - {( \sqrt{5} )}^{2} } - \frac{ {(7 - \sqrt{5}) }^{2} }{ {(7)}^{2} - {( \sqrt{5} )}^{2} } = a + 7b \sqrt{5} \\ \\ = > \frac{ {(7)}^{2} + {( \sqrt{5}) }^{2} + 2 \times 7 \times \sqrt{5} }{49 - 5} - \frac{ {(7)}^{2} + {( \sqrt{5} ) - 2 \times 7 \times \sqrt{5} }^{2} }{49 - 5} = a + 7b \sqrt{5} \\ \\ = > \frac{49 + 5 + 14 \sqrt{5} }{44} - \frac{(49 + 5 - 14 \sqrt{5} )}{44} = a + 7b \sqrt{5} \\ \\ = > \frac{54 + 14 \sqrt{5} }{44} - \frac{(54 - 14 \sqrt{5} )}{44} = a + 7b \sqrt{5} \\ \\ = > \frac{54 + 14 \sqrt{5} - 54 + 14 \sqrt{5} }{44} = a + 7b \sqrt{5} \\ \\ = > \frac{14 \sqrt{5} + 14 \sqrt{5} }{44} = a + 7b \sqrt{5} \\ \\ = > \frac{28 \sqrt{5} }{44} = a + 7b \sqrt{5}$

accordιng тo тнιѕ eqυaтιon:

a = 0

$= > \frac{28 \sqrt{5} }{44} = a + 7b \sqrt{5} \\ \\ = > \frac{28 \sqrt{5} }{44} = 0 + \frac{7 \times 4 \times \sqrt{5} }{44}$

нence, в = 4/44

тнanĸѕ !!