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hey mate.....
we know that
angle BAC + angle ABC = angle BCD
angle BAC + 63 = 125
angle BAC = 62
so we can prove that angle BAC = 62
hence sita is correct
HOPE THIS HELPS YOU ☺ ☺
we know that
angle BAC + angle ABC = angle BCD
angle BAC + 63 = 125
angle BAC = 62
so we can prove that angle BAC = 62
hence sita is correct
HOPE THIS HELPS YOU ☺ ☺
dhruvraj2208:
, ok
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- Given ∠ABC = 63
- Exterior angle is 125
- we know that the exterior angle so formed is equal to the sum of the two interior opposite angles in a triangle
- Here 125 = 63 +∠BAC
- therefore, by transposing, we can get that ∠BAC is equal to 62
- hence sita"s answer is correct
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