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In a GP
a=1
r=term 2/term 1
=-1/3/1
=-1/3
Sn=a(r^n-1)/r-1
=1[(-1/3)^n-1]/-1/3-1
=1[(-1/3)^n-1]/-4/3
=1x-3/4[(-1/3)^n-1]
=-3/4[(-1/3)^n-1]
In a GP
a=1
r=term 2/term 1
=-1/3/1
=-1/3
Sn=a(r^n-1)/r-1
=1[(-1/3)^n-1]/-1/3-1
=1[(-1/3)^n-1]/-4/3
=1x-3/4[(-1/3)^n-1]
=-3/4[(-1/3)^n-1]
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